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14223230122307 is a prime number
BaseRepresentation
bin1100111011111001101010…
…0101000011100101000011
31212100201122100210010022012
43032332122211003211003
53331013133402403212
650130021155203135
72665410621156503
oct316763245034503
955321570703265
1014223230122307
114594046672578
121718682ba64ab
137c2324c0510b
1437259d821a03
15199ea398b922
hexcef9a943943

14223230122307 has 2 divisors, whose sum is σ = 14223230122308. Its totient is φ = 14223230122306.

The previous prime is 14223230122279. The next prime is 14223230122313. The reversal of 14223230122307 is 70322103232241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14223230122307 - 216 = 14223230056771 is a prime.

It is a super-3 number, since 3×142232301223073 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (14223230122357) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111615061153 + 7111615061154.

It is an arithmetic number, because the mean of its divisors is an integer number (7111615061154).

Almost surely, 214223230122307 is an apocalyptic number.

14223230122307 is a deficient number, since it is larger than the sum of its proper divisors (1).

14223230122307 is an equidigital number, since it uses as much as digits as its factorization.

14223230122307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 32.

Adding to 14223230122307 its reverse (70322103232241), we get a palindrome (84545333354548).

The spelling of 14223230122307 in words is "fourteen trillion, two hundred twenty-three billion, two hundred thirty million, one hundred twenty-two thousand, three hundred seven".