Base | Representation |
---|---|
bin | 1000010001110110110… |
… | …1100101110100001111 |
3 | 111121010102101010111011 |
4 | 2010131231211310033 |
5 | 4312242444131112 |
6 | 145201330110051 |
7 | 13163436356242 |
oct | 2043555456417 |
9 | 447112333434 |
10 | 142232411407 |
11 | 55358540949 |
12 | 2369541b327 |
13 | 105492310a8 |
14 | 6c53d05259 |
15 | 3a76be1aa7 |
hex | 211db65d0f |
142232411407 has 2 divisors, whose sum is σ = 142232411408. Its totient is φ = 142232411406.
The previous prime is 142232411339. The next prime is 142232411443. The reversal of 142232411407 is 704114232241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142232411407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142232411107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71116205703 + 71116205704.
It is an arithmetic number, because the mean of its divisors is an integer number (71116205704).
Almost surely, 2142232411407 is an apocalyptic number.
142232411407 is a deficient number, since it is larger than the sum of its proper divisors (1).
142232411407 is an equidigital number, since it uses as much as digits as its factorization.
142232411407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10752, while the sum is 31.
Adding to 142232411407 its reverse (704114232241), we get a palindrome (846346643648).
The spelling of 142232411407 in words is "one hundred forty-two billion, two hundred thirty-two million, four hundred eleven thousand, four hundred seven".
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