Base | Representation |
---|---|
bin | 10100101100101001100… |
… | …011001000011010100101 |
3 | 12000222021201011211222211 |
4 | 110230221203020122211 |
5 | 141300413300002331 |
6 | 3005224314523421 |
7 | 204521460102121 |
oct | 24545143103245 |
9 | 5028251154884 |
10 | 1422331250341 |
11 | 4a9230a02191 |
12 | 1ab7a7a36571 |
13 | a4182278a81 |
14 | 4cbac376581 |
15 | 26ee88c18b1 |
hex | 14b298c86a5 |
1422331250341 has 2 divisors, whose sum is σ = 1422331250342. Its totient is φ = 1422331250340.
The previous prime is 1422331250317. The next prime is 1422331250359. The reversal of 1422331250341 is 1430521332241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1420218009441 + 2113240900 = 1191729^2 + 45970^2 .
It is a cyclic number.
It is not a de Polignac number, because 1422331250341 - 225 = 1422297695909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1422331256341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711165625170 + 711165625171.
It is an arithmetic number, because the mean of its divisors is an integer number (711165625171).
Almost surely, 21422331250341 is an apocalyptic number.
It is an amenable number.
1422331250341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1422331250341 is an equidigital number, since it uses as much as digits as its factorization.
1422331250341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 1422331250341 its reverse (1430521332241), we get a palindrome (2852852582582).
The spelling of 1422331250341 in words is "one trillion, four hundred twenty-two billion, three hundred thirty-one million, two hundred fifty thousand, three hundred forty-one".
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