Base | Representation |
---|---|
bin | 1100111011111001111110… |
… | …0100100101000010011011 |
3 | 1212100201212012101121202212 |
4 | 3032332133210211002123 |
5 | 3331013321323231131 |
6 | 50130033350345335 |
7 | 2665412656135562 |
oct | 316763744450233 |
9 | 55321765347685 |
10 | 14223313883291 |
11 | 4594089982427 |
12 | 17186a705b24b |
13 | 7c2339381326 |
14 | 3725aa9c6bd9 |
15 | 199eaaed4a2b |
hex | cef9f92509b |
14223313883291 has 2 divisors, whose sum is σ = 14223313883292. Its totient is φ = 14223313883290.
The previous prime is 14223313883239. The next prime is 14223313883293. The reversal of 14223313883291 is 19238831332241.
It is a strong prime.
It is an emirp because it is prime and its reverse (19238831332241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14223313883291 - 214 = 14223313866907 is a prime.
Together with 14223313883293, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14223313883293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111656941645 + 7111656941646.
It is an arithmetic number, because the mean of its divisors is an integer number (7111656941646).
Almost surely, 214223313883291 is an apocalyptic number.
14223313883291 is a deficient number, since it is larger than the sum of its proper divisors (1).
14223313883291 is an equidigital number, since it uses as much as digits as its factorization.
14223313883291 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1492992, while the sum is 50.
The spelling of 14223313883291 in words is "fourteen trillion, two hundred twenty-three billion, three hundred thirteen million, eight hundred eighty-three thousand, two hundred ninety-one".
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