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14223421203437 is a prime number
BaseRepresentation
bin1100111011111010010111…
…1101111110001111101101
31212100202010200100001100002
43032332211331332033231
53331014031312002222
650130052142514045
72665415431266365
oct316764575761755
955322120301302
1014223421203437
114594134513666
121718716b95925
137c2355688984
143725bad619a5
15199eb5633392
hexcefa5f7e3ed

14223421203437 has 2 divisors, whose sum is σ = 14223421203438. Its totient is φ = 14223421203436.

The previous prime is 14223421203419. The next prime is 14223421203473. The reversal of 14223421203437 is 73430212432241.

Together with next prime (14223421203473) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13696024262596 + 527396940841 = 3700814^2 + 726221^2 .

It is a cyclic number.

It is not a de Polignac number, because 14223421203437 - 216 = 14223421137901 is a prime.

It is a super-2 number, since 2×142234212034372 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14223421203437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14223421203137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111710601718 + 7111710601719.

It is an arithmetic number, because the mean of its divisors is an integer number (7111710601719).

Almost surely, 214223421203437 is an apocalyptic number.

It is an amenable number.

14223421203437 is a deficient number, since it is larger than the sum of its proper divisors (1).

14223421203437 is an equidigital number, since it uses as much as digits as its factorization.

14223421203437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 193536, while the sum is 38.

Adding to 14223421203437 its reverse (73430212432241), we get a palindrome (87653633635678).

The spelling of 14223421203437 in words is "fourteen trillion, two hundred twenty-three billion, four hundred twenty-one million, two hundred three thousand, four hundred thirty-seven".