Base | Representation |
---|---|
bin | 1100111011111010011100… |
… | …1010101001101000000011 |
3 | 1212100202012002011021012212 |
4 | 3032332213022221220003 |
5 | 3331014101433212232 |
6 | 50130054141412335 |
7 | 2665416064164662 |
oct | 316764712515003 |
9 | 55322162137185 |
10 | 14223441304067 |
11 | 45941448a2556 |
12 | 171872186a0ab |
13 | 7c23598a5b38 |
14 | 3725bd8b4dd9 |
15 | 199eb72a3eb2 |
hex | cefa72a9a03 |
14223441304067 has 2 divisors, whose sum is σ = 14223441304068. Its totient is φ = 14223441304066.
The previous prime is 14223441304019. The next prime is 14223441304087. The reversal of 14223441304067 is 76040314432241.
It is a strong prime.
It is an emirp because it is prime and its reverse (76040314432241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14223441304067 - 214 = 14223441287683 is a prime.
It is not a weakly prime, because it can be changed into another prime (14223441304087) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111720652033 + 7111720652034.
It is an arithmetic number, because the mean of its divisors is an integer number (7111720652034).
Almost surely, 214223441304067 is an apocalyptic number.
14223441304067 is a deficient number, since it is larger than the sum of its proper divisors (1).
14223441304067 is an equidigital number, since it uses as much as digits as its factorization.
14223441304067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 387072, while the sum is 41.
The spelling of 14223441304067 in words is "fourteen trillion, two hundred twenty-three billion, four hundred forty-one million, three hundred four thousand, sixty-seven".
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