Base | Representation |
---|---|
bin | 1100111011111010011100… |
… | …1010110011001000000111 |
3 | 1212100202012002020020121012 |
4 | 3032332213022303020013 |
5 | 3331014101440433413 |
6 | 50130054142312435 |
7 | 2665416064416305 |
oct | 316764712631007 |
9 | 55322162206535 |
10 | 14223441342983 |
11 | 4594144919814 |
12 | 171872188871b |
13 | 7c23598ba772 |
14 | 3725bd8c5275 |
15 | 199eb72b07a8 |
hex | cefa72b3207 |
14223441342983 has 2 divisors, whose sum is σ = 14223441342984. Its totient is φ = 14223441342982.
The previous prime is 14223441342947. The next prime is 14223441343037. The reversal of 14223441342983 is 38924314432241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14223441342983 - 26 = 14223441342919 is a prime.
It is a super-3 number, since 3×142234413429833 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14223441342883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111720671491 + 7111720671492.
It is an arithmetic number, because the mean of its divisors is an integer number (7111720671492).
Almost surely, 214223441342983 is an apocalyptic number.
14223441342983 is a deficient number, since it is larger than the sum of its proper divisors (1).
14223441342983 is an equidigital number, since it uses as much as digits as its factorization.
14223441342983 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3981312, while the sum is 50.
The spelling of 14223441342983 in words is "fourteen trillion, two hundred twenty-three billion, four hundred forty-one million, three hundred forty-two thousand, nine hundred eighty-three".
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