Base | Representation |
---|---|
bin | 1100111011111010011100… |
… | …1010110011001001000010 |
3 | 1212100202012002020020200101 |
4 | 3032332213022303021002 |
5 | 3331014101440434132 |
6 | 50130054142313014 |
7 | 2665416064416421 |
oct | 316764712631102 |
9 | 55322162206611 |
10 | 14223441343042 |
11 | 4594144919868 |
12 | 171872188876a |
13 | 7c23598ba7b9 |
14 | 3725bd8c52b8 |
15 | 199eb72b07e7 |
hex | cefa72b3242 |
14223441343042 has 4 divisors (see below), whose sum is σ = 21335162014566. Its totient is φ = 7111720671520.
The previous prime is 14223441343039. The next prime is 14223441343051. The reversal of 14223441343042 is 24034314432241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8700382028881 + 5523059314161 = 2949641^2 + 2350119^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14223441342992 and 14223441343010.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3555860335759 + ... + 3555860335762.
Almost surely, 214223441343042 is an apocalyptic number.
14223441343042 is a deficient number, since it is larger than the sum of its proper divisors (7111720671524).
14223441343042 is an equidigital number, since it uses as much as digits as its factorization.
14223441343042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7111720671523.
The product of its (nonzero) digits is 221184, while the sum is 37.
Adding to 14223441343042 its reverse (24034314432241), we get a palindrome (38257755775283).
The spelling of 14223441343042 in words is "fourteen trillion, two hundred twenty-three billion, four hundred forty-one million, three hundred forty-three thousand, forty-two".
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