Base | Representation |
---|---|
bin | 1100111011111010011111… |
… | …0000001011100101100111 |
3 | 1212100202012202200010000101 |
4 | 3032332213300023211213 |
5 | 3331014111443030003 |
6 | 50130055132324531 |
7 | 2665416243622321 |
oct | 316764760134547 |
9 | 55322182603011 |
10 | 14223451142503 |
11 | 459414a402299 |
12 | 1718725013747 |
13 | 7c235b93bcb5 |
14 | 3725c0d16611 |
15 | 199eb809911d |
hex | cefa7c0b967 |
14223451142503 has 4 divisors (see below), whose sum is σ = 14223459283888. Its totient is φ = 14223443001120.
The previous prime is 14223451142477. The next prime is 14223451142513. The reversal of 14223451142503 is 30524115432241.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14223451142503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14223451142513) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 262683 + ... + 5340028.
It is an arithmetic number, because the mean of its divisors is an integer number (3555864820972).
Almost surely, 214223451142503 is an apocalyptic number.
14223451142503 is a deficient number, since it is larger than the sum of its proper divisors (8141385).
14223451142503 is an equidigital number, since it uses as much as digits as its factorization.
14223451142503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8141384.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 14223451142503 its reverse (30524115432241), we get a palindrome (44747566574744).
The spelling of 14223451142503 in words is "fourteen trillion, two hundred twenty-three billion, four hundred fifty-one million, one hundred forty-two thousand, five hundred three".
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