Base | Representation |
---|---|
bin | 1100111011111100100010… |
… | …0111001011010110100101 |
3 | 1212100210122012000102210122 |
4 | 3032333020213023112211 |
5 | 3331021224110232443 |
6 | 50130225544331325 |
7 | 2665436016526511 |
oct | 316771047132645 |
9 | 55323565012718 |
10 | 14224002430373 |
11 | 4594402609aaa |
12 | 1718859773b45 |
13 | 7c2418c10738 |
14 | 37263421d141 |
15 | 199eeb693968 |
hex | cefc89cb5a5 |
14224002430373 has 2 divisors, whose sum is σ = 14224002430374. Its totient is φ = 14224002430372.
The previous prime is 14224002430349. The next prime is 14224002430433. The reversal of 14224002430373 is 37303420042241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14221700541889 + 2301888484 = 3771167^2 + 47978^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14224002430373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14224002450373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7112001215186 + 7112001215187.
It is an arithmetic number, because the mean of its divisors is an integer number (7112001215187).
Almost surely, 214224002430373 is an apocalyptic number.
It is an amenable number.
14224002430373 is a deficient number, since it is larger than the sum of its proper divisors (1).
14224002430373 is an equidigital number, since it uses as much as digits as its factorization.
14224002430373 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 35.
The spelling of 14224002430373 in words is "fourteen trillion, two hundred twenty-four billion, two million, four hundred thirty thousand, three hundred seventy-three".
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