Base | Representation |
---|---|
bin | 1100111011111100101100… |
… | …0001111111010100011111 |
3 | 1212100210202000101021020222 |
4 | 3032333023001333110133 |
5 | 3331021320002412112 |
6 | 50130233554231555 |
7 | 2665440021503423 |
oct | 316771301772437 |
9 | 55323660337228 |
10 | 14224043013407 |
11 | 45944235086a7 |
12 | 171886b2855bb |
13 | 7c242444c776 |
14 | 372639784b83 |
15 | 19a00000d372 |
hex | cefcb07f51f |
14224043013407 has 2 divisors, whose sum is σ = 14224043013408. Its totient is φ = 14224043013406.
The previous prime is 14224043013403. The next prime is 14224043013413. The reversal of 14224043013407 is 70431034042241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14224043013407 - 22 = 14224043013403 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14224043013403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7112021506703 + 7112021506704.
It is an arithmetic number, because the mean of its divisors is an integer number (7112021506704).
Almost surely, 214224043013407 is an apocalyptic number.
14224043013407 is a deficient number, since it is larger than the sum of its proper divisors (1).
14224043013407 is an equidigital number, since it uses as much as digits as its factorization.
14224043013407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 14224043013407 its reverse (70431034042241), we get a palindrome (84655077055648).
The spelling of 14224043013407 in words is "fourteen trillion, two hundred twenty-four billion, forty-three million, thirteen thousand, four hundred seven".
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