Base | Representation |
---|---|
bin | 1100111011111100111001… |
… | …1011111000010010101011 |
3 | 1212100210212222212012020211 |
4 | 3032333032123320102223 |
5 | 3331021424113211021 |
6 | 50130243354401551 |
7 | 2665441314140110 |
oct | 316771633702253 |
9 | 55323788765224 |
10 | 14224100132011 |
11 | 4594452780760 |
12 | 17188864302b7 |
13 | 7c243322b063 |
14 | 3726431b2907 |
15 | 19a0050423e1 |
hex | cefce6f84ab |
14224100132011 has 32 divisors (see below), whose sum is σ = 18241391434752. Its totient is φ = 10767485208960.
The previous prime is 14224100131993. The next prime is 14224100132087. The reversal of 14224100132011 is 11023100142241.
It is a cyclic number.
It is not a de Polignac number, because 14224100132011 - 229 = 14223563261099 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14224100133011) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2015016 + ... + 5701621.
It is an arithmetic number, because the mean of its divisors is an integer number (570043482336).
Almost surely, 214224100132011 is an apocalyptic number.
14224100132011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
14224100132011 is a deficient number, since it is larger than the sum of its proper divisors (4017291302741).
14224100132011 is a wasteful number, since it uses less digits than its factorization.
14224100132011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7717339.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 14224100132011 its reverse (11023100142241), we get a palindrome (25247200274252).
The spelling of 14224100132011 in words is "fourteen trillion, two hundred twenty-four billion, one hundred million, one hundred thirty-two thousand, eleven".
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