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1422424244447 is a prime number
BaseRepresentation
bin10100101100101111000…
…101111000000011011111
312000222112012011102220222
4110230233011320003133
5141301111101310242
63005241440031555
7204523666405013
oct24545705700337
95028465142828
101422424244447
114a9279449018
121ab8130025bb
13a419860877b
144cbba862543
1527001b405d2
hex14b2f1780df

1422424244447 has 2 divisors, whose sum is σ = 1422424244448. Its totient is φ = 1422424244446.

The previous prime is 1422424244431. The next prime is 1422424244497. The reversal of 1422424244447 is 7444424242241.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1422424244447 - 24 = 1422424244431 is a prime.

It is a super-3 number, since 3×14224242444473 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1422424244398 and 1422424244407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1422424244497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711212122223 + 711212122224.

It is an arithmetic number, because the mean of its divisors is an integer number (711212122224).

Almost surely, 21422424244447 is an apocalyptic number.

1422424244447 is a deficient number, since it is larger than the sum of its proper divisors (1).

1422424244447 is an equidigital number, since it uses as much as digits as its factorization.

1422424244447 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1835008, while the sum is 44.

Adding to 1422424244447 its reverse (7444424242241), we get a palindrome (8866848486688).

The spelling of 1422424244447 in words is "one trillion, four hundred twenty-two billion, four hundred twenty-four million, two hundred forty-four thousand, four hundred forty-seven".