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14224322441311 is a prime number
BaseRepresentation
bin1100111011111101101110…
…1011111011000001011111
31212100211110111011200021121
43032333123223323001133
53331022403021110221
650130321415311411
72665446653552143
oct316773353730137
955324414150247
1014224322441311
114594557210a54
12171892897b567
137c246a2c6918
14372664921223
1519a019806a41
hexcefdbafb05f

14224322441311 has 2 divisors, whose sum is σ = 14224322441312. Its totient is φ = 14224322441310.

The previous prime is 14224322441293. The next prime is 14224322441339. The reversal of 14224322441311 is 11314422342241.

It is a weak prime.

It is an emirp because it is prime and its reverse (11314422342241) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14224322441311 is a prime.

It is a super-3 number, since 3×142243224413113 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14224322441611) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7112161220655 + 7112161220656.

It is an arithmetic number, because the mean of its divisors is an integer number (7112161220656).

Almost surely, 214224322441311 is an apocalyptic number.

14224322441311 is a deficient number, since it is larger than the sum of its proper divisors (1).

14224322441311 is an equidigital number, since it uses as much as digits as its factorization.

14224322441311 is an evil number, because the sum of its binary digits is even.

The product of its digits is 36864, while the sum is 34.

Adding to 14224322441311 its reverse (11314422342241), we get a palindrome (25538744783552).

The spelling of 14224322441311 in words is "fourteen trillion, two hundred twenty-four billion, three hundred twenty-two million, four hundred forty-one thousand, three hundred eleven".