Base | Representation |
---|---|
bin | 1100111011111110000010… |
… | …0100010100000111011111 |
3 | 1212100211200012021012120222 |
4 | 3032333200210110013133 |
5 | 3331023040002124043 |
6 | 50130333502431555 |
7 | 2665451666614403 |
oct | 316774044240737 |
9 | 55324605235528 |
10 | 14224404333023 |
11 | 4594599464455 |
12 | 17189502925bb |
13 | 7c248126a061 |
14 | 37267175b103 |
15 | 19a021ad0d68 |
hex | cefe09141df |
14224404333023 has 2 divisors, whose sum is σ = 14224404333024. Its totient is φ = 14224404333022.
The previous prime is 14224404332977. The next prime is 14224404333037. The reversal of 14224404333023 is 32033340442241.
It is a strong prime.
It is an emirp because it is prime and its reverse (32033340442241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14224404333023 - 222 = 14224400138719 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14224404333523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7112202166511 + 7112202166512.
It is an arithmetic number, because the mean of its divisors is an integer number (7112202166512).
Almost surely, 214224404333023 is an apocalyptic number.
14224404333023 is a deficient number, since it is larger than the sum of its proper divisors (1).
14224404333023 is an equidigital number, since it uses as much as digits as its factorization.
14224404333023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 35.
Adding to 14224404333023 its reverse (32033340442241), we get a palindrome (46257744775264).
The spelling of 14224404333023 in words is "fourteen trillion, two hundred twenty-four billion, four hundred four million, three hundred thirty-three thousand, twenty-three".
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