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1422500235545 = 5284500047109
BaseRepresentation
bin10100101100110011100…
…111110000100100011001
312000222201111011012010002
4110230303213300210121
5141301240030014140
63005253152502345
7204525611333264
oct24546347604431
95028644135102
101422500235545
114a9308331284
121ab83454a9b5
13a41ab29420c
144cbc69a3cdb
1527008651415
hex14b339f0919

1422500235545 has 4 divisors (see below), whose sum is σ = 1707000282660. Its totient is φ = 1138000188432.

The previous prime is 1422500235503. The next prime is 1422500235553. The reversal of 1422500235545 is 5455320052241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1106173855504 + 316326380041 = 1051748^2 + 562429^2 .

It is a cyclic number.

It is not a de Polignac number, because 1422500235545 - 234 = 1405320366361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1422500235499 and 1422500235508.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142250023550 + ... + 142250023559.

It is an arithmetic number, because the mean of its divisors is an integer number (426750070665).

Almost surely, 21422500235545 is an apocalyptic number.

It is an amenable number.

1422500235545 is a deficient number, since it is larger than the sum of its proper divisors (284500047115).

1422500235545 is an equidigital number, since it uses as much as digits as its factorization.

1422500235545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 284500047114.

The product of its (nonzero) digits is 240000, while the sum is 38.

Adding to 1422500235545 its reverse (5455320052241), we get a palindrome (6877820287786).

The spelling of 1422500235545 in words is "one trillion, four hundred twenty-two billion, five hundred million, two hundred thirty-five thousand, five hundred forty-five".

Divisors: 1 5 284500047109 1422500235545