Base | Representation |
---|---|
bin | 11010011111111000… |
… | …10100000000011111 |
3 | 1100201102221101200011 |
4 | 31033330110000133 |
5 | 213113341100133 |
6 | 10311350544051 |
7 | 1012351650526 |
oct | 151774240037 |
9 | 40642841604 |
10 | 14226112543 |
11 | 60402a6a05 |
12 | 2910368027 |
13 | 1459409896 |
14 | 98d5354bd |
15 | 583de96cd |
hex | 34ff1401f |
14226112543 has 4 divisors (see below), whose sum is σ = 14263648840. Its totient is φ = 14188576248.
The previous prime is 14226112517. The next prime is 14226112547. The reversal of 14226112543 is 34521162241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14226112543 - 213 = 14226104351 is a prime.
It is a super-2 number, since 2×142261125432 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14226112547) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18767580 + ... + 18768337.
It is an arithmetic number, because the mean of its divisors is an integer number (3565912210).
Almost surely, 214226112543 is an apocalyptic number.
14226112543 is a deficient number, since it is larger than the sum of its proper divisors (37536297).
14226112543 is an equidigital number, since it uses as much as digits as its factorization.
14226112543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37536296.
The product of its digits is 11520, while the sum is 31.
Adding to 14226112543 its reverse (34521162241), we get a palindrome (48747274784).
The spelling of 14226112543 in words is "fourteen billion, two hundred twenty-six million, one hundred twelve thousand, five hundred forty-three".
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