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142300031232439 is a prime number
BaseRepresentation
bin100000010110101111001110…
…110100000010100110110111
3200122211202020211210012011101
4200112233032310002212313
5122122420430443414224
61222351422030350531
741654560300140253
oct4026571664024667
9618752224705141
10142300031232439
1141383116970763
1213b6284865b447
136152ab23ba5b2
14271d5030cd263
15116b83c797044
hex816bced029b7

142300031232439 has 2 divisors, whose sum is σ = 142300031232440. Its totient is φ = 142300031232438.

The previous prime is 142300031232427. The next prime is 142300031232461. The reversal of 142300031232439 is 934232130003241.

142300031232439 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 142300031232439 - 215 = 142300031199671 is a prime.

It is a super-2 number, since 2×1423000312324392 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 142300031232398 and 142300031232407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142300031232409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71150015616219 + 71150015616220.

It is an arithmetic number, because the mean of its divisors is an integer number (71150015616220).

Almost surely, 2142300031232439 is an apocalyptic number.

142300031232439 is a deficient number, since it is larger than the sum of its proper divisors (1).

142300031232439 is an equidigital number, since it uses as much as digits as its factorization.

142300031232439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 93312, while the sum is 37.

The spelling of 142300031232439 in words is "one hundred forty-two trillion, three hundred billion, thirty-one million, two hundred thirty-two thousand, four hundred thirty-nine".