Base | Representation |
---|---|
bin | 100000010110101111001110… |
… | …110100101011100100111011 |
3 | 200122211202020212002201100122 |
4 | 200112233032310223210323 |
5 | 122122420431014302001 |
6 | 1222351422034123455 |
7 | 41654560301436434 |
oct | 4026571664534473 |
9 | 618752225081318 |
10 | 142300031400251 |
11 | 41383116a7584a |
12 | 13b6284872058b |
13 | 6152ab2448aaa |
14 | 271d50313448b |
15 | 116b83c7cbb1b |
hex | 816bced2b93b |
142300031400251 has 2 divisors, whose sum is σ = 142300031400252. Its totient is φ = 142300031400250.
The previous prime is 142300031400229. The next prime is 142300031400269. The reversal of 142300031400251 is 152004130003241.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142300031400251 - 26 = 142300031400187 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 142300031400251.
It is not a weakly prime, because it can be changed into another prime (142300031400151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71150015700125 + 71150015700126.
It is an arithmetic number, because the mean of its divisors is an integer number (71150015700126).
Almost surely, 2142300031400251 is an apocalyptic number.
142300031400251 is a deficient number, since it is larger than the sum of its proper divisors (1).
142300031400251 is an equidigital number, since it uses as much as digits as its factorization.
142300031400251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 142300031400251 its reverse (152004130003241), we get a palindrome (294304161403492).
The spelling of 142300031400251 in words is "one hundred forty-two trillion, three hundred billion, thirty-one million, four hundred thousand, two hundred fifty-one".
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