142300031400401 has 4 divisors (see below), whose sum is σ = 162628607314752. Its totient is φ = 121971455486052.

The previous prime is 142300031400377. The next prime is 142300031400407. The reversal of 142300031400401 is 104004130003241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142300031400401 - 2⁶ = 142300031400337 is a prime.

It is a super-2 number, since 2×142300031400401² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142300031400407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10164287957165 + ... + 10164287957178.

It is an arithmetic number, because the mean of its divisors is an integer number (40657151828688).

Almost surely, 2^{142300031400401} is an apocalyptic number.

It is an amenable number.

142300031400401 is a deficient number, since it is larger than the sum of its proper divisors (20328575914351).

142300031400401 is an equidigital number, since it uses as much as digits as its factorization.

142300031400401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20328575914350.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 142300031400401 its reverse (104004130003241), we get a palindrome (246304161403642).

The spelling of 142300031400401 in words is "one hundred forty-two trillion, three hundred billion, thirty-one million, four hundred thousand, four hundred one".