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142301130887623 is a prime number
BaseRepresentation
bin100000010110110000010000…
…010110111001000111000111
3200122211212002110222110111011
4200112300100112321013013
5122122430204001400443
61222352123112023051
741654626452066121
oct4026602026710707
9618755073873434
10142301130887623
114138363066a9a4
1213b62ab4991a87
136152c2917a336
14271d5a917c211
15116b8a40b0b9d
hex816c105b91c7

142301130887623 has 2 divisors, whose sum is σ = 142301130887624. Its totient is φ = 142301130887622.

The previous prime is 142301130887567. The next prime is 142301130887659. The reversal of 142301130887623 is 326788031103241.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142301130887623 is a prime.

It is a super-2 number, since 2×1423011308876232 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142301130887023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71150565443811 + 71150565443812.

It is an arithmetic number, because the mean of its divisors is an integer number (71150565443812).

Almost surely, 2142301130887623 is an apocalyptic number.

142301130887623 is a deficient number, since it is larger than the sum of its proper divisors (1).

142301130887623 is an equidigital number, since it uses as much as digits as its factorization.

142301130887623 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1161216, while the sum is 49.

The spelling of 142301130887623 in words is "one hundred forty-two trillion, three hundred one billion, one hundred thirty million, eight hundred eighty-seven thousand, six hundred twenty-three".