Base | Representation |
---|---|
bin | 11010100000011000… |
… | …10010111011110011 |
3 | 1100201201211021010221 |
4 | 31100030102323303 |
5 | 213120424134301 |
6 | 10312020433511 |
7 | 1012432401151 |
oct | 152014227363 |
9 | 40651737127 |
10 | 14230302451 |
11 | 60426a8942 |
12 | 2911848897 |
13 | 145a245a11 |
14 | 98dd063d1 |
15 | 584475da1 |
hex | 350312ef3 |
14230302451 has 2 divisors, whose sum is σ = 14230302452. Its totient is φ = 14230302450.
The previous prime is 14230302413. The next prime is 14230302461. The reversal of 14230302451 is 15420303241.
14230302451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14230302451 - 27 = 14230302323 is a prime.
It is not a weakly prime, because it can be changed into another prime (14230302461) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115151225 + 7115151226.
It is an arithmetic number, because the mean of its divisors is an integer number (7115151226).
Almost surely, 214230302451 is an apocalyptic number.
14230302451 is a deficient number, since it is larger than the sum of its proper divisors (1).
14230302451 is an equidigital number, since it uses as much as digits as its factorization.
14230302451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 14230302451 its reverse (15420303241), we get a palindrome (29650605692).
The spelling of 14230302451 in words is "fourteen billion, two hundred thirty million, three hundred two thousand, four hundred fifty-one".
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