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14230314411 = 34743438137
BaseRepresentation
bin11010100000011000…
…10101110110101011
31100201201211212112220
431100030111312223
5213120430030121
610312021005123
71012432451055
oct152014256653
940651755486
1014230314411
116042706925
1229118537a3
13145a24b2b1
1498dd0a8d5
155844796c6
hex350315dab

14230314411 has 4 divisors (see below), whose sum is σ = 18973752552. Its totient is φ = 9486876272.

The previous prime is 14230314353. The next prime is 14230314437. The reversal of 14230314411 is 11441303241.

14230314411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14230314411 - 213 = 14230306219 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14230314011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2371719066 + ... + 2371719071.

It is an arithmetic number, because the mean of its divisors is an integer number (4743438138).

Almost surely, 214230314411 is an apocalyptic number.

14230314411 is a deficient number, since it is larger than the sum of its proper divisors (4743438141).

14230314411 is an equidigital number, since it uses as much as digits as its factorization.

14230314411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4743438140.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 14230314411 its reverse (11441303241), we get a palindrome (25671617652).

The spelling of 14230314411 in words is "fourteen billion, two hundred thirty million, three hundred fourteen thousand, four hundred eleven".

Divisors: 1 3 4743438137 14230314411