Base | Representation |
---|---|
bin | 11010100000011100… |
… | …10101101011101010 |
3 | 1100201202211110202212 |
4 | 31100032111223222 |
5 | 213121043303434 |
6 | 10312040125122 |
7 | 1012440061412 |
oct | 152016255352 |
9 | 40652743685 |
10 | 14230837994 |
11 | 6042a3423a |
12 | 2911a667a2 |
13 | 145a3a26c9 |
14 | 990005642 |
15 | 58452e8ce |
hex | 350395aea |
14230837994 has 4 divisors (see below), whose sum is σ = 21346256994. Its totient is φ = 7115418996.
The previous prime is 14230837993. The next prime is 14230838059. The reversal of 14230837994 is 49973803241.
14230837994 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 49973803241 = 17203 ⋅2904947.
It can be written as a sum of positive squares in only one way, i.e., 13478049025 + 752788969 = 116095^2 + 27437^2 .
It is a super-2 number, since 2×142308379942 (a number of 21 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (14230837993) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3557709497 + ... + 3557709500.
Almost surely, 214230837994 is an apocalyptic number.
14230837994 is a deficient number, since it is larger than the sum of its proper divisors (7115419000).
14230837994 is an equidigital number, since it uses as much as digits as its factorization.
14230837994 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7115418999.
The product of its (nonzero) digits is 1306368, while the sum is 50.
The spelling of 14230837994 in words is "fourteen billion, two hundred thirty million, eight hundred thirty-seven thousand, nine hundred ninety-four".
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