14231112433 has 8 divisors (see below), whose sum is σ = 14692285440. Its totient is φ = 13770071040.

The previous prime is 14231112407. The next prime is 14231112449. The reversal of 14231112433 is 33421113241.

14231112433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2^k-14231112433 is a prime.

It is a super-2 number, since 2×14231112433² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14231112398 and 14231112407.

It is not an unprimeable number, because it can be changed into a prime (14231112463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 217128 + ... + 274966.

It is an arithmetic number, because the mean of its divisors is an integer number (1836535680).

Almost surely, 2^14231112433 is an apocalyptic number.

It is an amenable number.

14231112433 is a deficient number, since it is larger than the sum of its proper divisors (461173007).

14231112433 is an equidigital number, since it uses as much as digits as its factorization.

14231112433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65807.

The product of its digits is 1728, while the sum is 25.

Adding to 14231112433 its reverse (33421113241), we get a palindrome (47652225674).

The spelling of 14231112433 in words is "fourteen billion, two hundred thirty-one million, one hundred twelve thousand, four hundred thirty-three".