Base | Representation |
---|---|
bin | 100000010110111010100000… |
… | …001100110111000001000110 |
3 | 200122212220111022111010210002 |
4 | 200112322200030313001012 |
5 | 122123120222313030202 |
6 | 1222401143013201302 |
7 | 41655466230666341 |
oct | 4026724014670106 |
9 | 618786438433702 |
10 | 142312134111302 |
11 | 413882676aa791 |
12 | 13b65065930232 |
13 | 6153c9096308c |
14 | 271dd3064b458 |
15 | 116bcea08a302 |
hex | 816ea0337046 |
142312134111302 has 8 divisors (see below), whose sum is σ = 215426625031200. Its totient is φ = 70503259100904.
The previous prime is 142312134111151. The next prime is 142312134111307. The reversal of 142312134111302 is 203111431213241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142312134111307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 326403977102 + ... + 326403977537.
It is an arithmetic number, because the mean of its divisors is an integer number (26928328128900).
Almost surely, 2142312134111302 is an apocalyptic number.
142312134111302 is a deficient number, since it is larger than the sum of its proper divisors (73114490919898).
142312134111302 is a wasteful number, since it uses less digits than its factorization.
142312134111302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 652807954750.
The product of its (nonzero) digits is 3456, while the sum is 29.
Adding to 142312134111302 its reverse (203111431213241), we get a palindrome (345423565324543).
The spelling of 142312134111302 in words is "one hundred forty-two trillion, three hundred twelve billion, one hundred thirty-four million, one hundred eleven thousand, three hundred two".
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