Base | Representation |
---|---|
bin | 1000010010001001111… |
… | …1110000111111110011 |
3 | 111121100000101212001122 |
4 | 2010202133300333303 |
5 | 4312424021021032 |
6 | 145213314252455 |
7 | 13165432522652 |
oct | 2044237607763 |
9 | 447300355048 |
10 | 142312673267 |
11 | 55399880866 |
12 | 236b828712b |
13 | 1055ca5370b |
14 | 6c60839199 |
15 | 3a7dc98012 |
hex | 21227f0ff3 |
142312673267 has 2 divisors, whose sum is σ = 142312673268. Its totient is φ = 142312673266.
The previous prime is 142312673219. The next prime is 142312673311. The reversal of 142312673267 is 762376213241.
It is an a-pointer prime, because the next prime (142312673311) can be obtained adding 142312673267 to its sum of digits (44).
It is a strong prime.
It is an emirp because it is prime and its reverse (762376213241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 142312673267 - 232 = 138017705971 is a prime.
It is not a weakly prime, because it can be changed into another prime (142302673267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71156336633 + 71156336634.
It is an arithmetic number, because the mean of its divisors is an integer number (71156336634).
Almost surely, 2142312673267 is an apocalyptic number.
142312673267 is a deficient number, since it is larger than the sum of its proper divisors (1).
142312673267 is an equidigital number, since it uses as much as digits as its factorization.
142312673267 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 508032, while the sum is 44.
The spelling of 142312673267 in words is "one hundred forty-two billion, three hundred twelve million, six hundred seventy-three thousand, two hundred sixty-seven".
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