Base | Representation |
---|---|
bin | 11010100000100001… |
… | …01100101110000111 |
3 | 1100201210222220101221 |
4 | 31100100230232013 |
5 | 213121223103042 |
6 | 10312101301211 |
7 | 1012445246152 |
oct | 152020545607 |
9 | 40653886357 |
10 | 14231456647 |
11 | 6043317021 |
12 | 2912104807 |
13 | 145a55b185 |
14 | 990126c99 |
15 | 584602d67 |
hex | 35042cb87 |
14231456647 has 2 divisors, whose sum is σ = 14231456648. Its totient is φ = 14231456646.
The previous prime is 14231456467. The next prime is 14231456663. The reversal of 14231456647 is 74665413241.
Together with previous prime (14231456467) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is an emirp because it is prime and its reverse (74665413241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14231456647 - 211 = 14231454599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14231456677) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115728323 + 7115728324.
It is an arithmetic number, because the mean of its divisors is an integer number (7115728324).
Almost surely, 214231456647 is an apocalyptic number.
14231456647 is a deficient number, since it is larger than the sum of its proper divisors (1).
14231456647 is an equidigital number, since it uses as much as digits as its factorization.
14231456647 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 483840, while the sum is 43.
Adding to 14231456647 its reverse (74665413241), we get a palindrome (88896869888).
The spelling of 14231456647 in words is "fourteen billion, two hundred thirty-one million, four hundred fifty-six thousand, six hundred forty-seven".
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