Base | Representation |
---|---|
bin | 100000010111000010110001… |
… | …011001000001010000100111 |
3 | 200122220202102001122021201021 |
4 | 200113002301121001100213 |
5 | 122123241413141234442 |
6 | 1222405212010512011 |
7 | 41656232235412645 |
oct | 4027026131012047 |
9 | 618822361567637 |
10 | 142321012446247 |
11 | 41391003252188 |
12 | 13b66923135607 |
13 | 6154a771555cb |
14 | 2720533832195 |
15 | 116c169732e67 |
hex | 8170b1641427 |
142321012446247 has 2 divisors, whose sum is σ = 142321012446248. Its totient is φ = 142321012446246.
The previous prime is 142321012446049. The next prime is 142321012446343. The reversal of 142321012446247 is 742644210123241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142321012446247 - 235 = 142286652707879 is a prime.
It is a super-3 number, since 3×1423210124462473 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142321022446247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71160506223123 + 71160506223124.
It is an arithmetic number, because the mean of its divisors is an integer number (71160506223124).
Almost surely, 2142321012446247 is an apocalyptic number.
142321012446247 is a deficient number, since it is larger than the sum of its proper divisors (1).
142321012446247 is an equidigital number, since it uses as much as digits as its factorization.
142321012446247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 516096, while the sum is 43.
Adding to 142321012446247 its reverse (742644210123241), we get a palindrome (884965222569488).
The spelling of 142321012446247 in words is "one hundred forty-two trillion, three hundred twenty-one billion, twelve million, four hundred forty-six thousand, two hundred forty-seven".
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