142321023413641 has 4 divisors (see below), whose sum is σ = 142931843256852. Its totient is φ = 141710203570432.

The previous prime is 142321023413629. The next prime is 142321023413651. The reversal of 142321023413641 is 146314320123241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 50646066726025 + 91674956687616 = 7116605^2 + 9574704^2 .

It is a cyclic number.

It is not a de Polignac number, because 142321023413641 - 2⁴¹ = 140122000158089 is a prime.

It is a super-2 number, since 2×142321023413641² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 142321023413641.

It is not an unprimeable number, because it can be changed into a prime (142321023413651) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 305409921256 + ... + 305409921721.

It is an arithmetic number, because the mean of its divisors is an integer number (35732960814213).

Almost surely, 2^{142321023413641} is an apocalyptic number.

It is an amenable number.

142321023413641 is a deficient number, since it is larger than the sum of its proper divisors (610819843211).

142321023413641 is an equidigital number, since it uses as much as digits as its factorization.

142321023413641 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 610819843210.

The product of its (nonzero) digits is 82944, while the sum is 37.

Adding to 142321023413641 its reverse (146314320123241), we get a palindrome (288635343536882).

The spelling of 142321023413641 in words is "one hundred forty-two trillion, three hundred twenty-one billion, twenty-three million, four hundred thirteen thousand, six hundred forty-one".