Base | Representation |
---|---|
bin | 100000010111000010110010… |
… | …000011001110110111010101 |
3 | 200122220202102211110111002202 |
4 | 200113002302003032313111 |
5 | 122123241424004341041 |
6 | 1222405213044014245 |
7 | 41656232431441454 |
oct | 4027026203166725 |
9 | 618822384414082 |
10 | 142321023512021 |
11 | 41391009520052 |
12 | 13b66926991385 |
13 | 6154a7952b2c3 |
14 | 27205350b2b9b |
15 | 116c16a6bba9b |
hex | 8170b20cedd5 |
142321023512021 has 2 divisors, whose sum is σ = 142321023512022. Its totient is φ = 142321023512020.
The previous prime is 142321023512011. The next prime is 142321023512153. The reversal of 142321023512021 is 120215320123241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 91105688704900 + 51215334807121 = 9544930^2 + 7156489^2 .
It is a cyclic number.
It is not a de Polignac number, because 142321023512021 - 26 = 142321023511957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142321023512011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71160511756010 + 71160511756011.
It is an arithmetic number, because the mean of its divisors is an integer number (71160511756011).
Almost surely, 2142321023512021 is an apocalyptic number.
It is an amenable number.
142321023512021 is a deficient number, since it is larger than the sum of its proper divisors (1).
142321023512021 is an equidigital number, since it uses as much as digits as its factorization.
142321023512021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 142321023512021 its reverse (120215320123241), we get a palindrome (262536343635262).
The spelling of 142321023512021 in words is "one hundred forty-two trillion, three hundred twenty-one billion, twenty-three million, five hundred twelve thousand, twenty-one".
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