Base | Representation |
---|---|
bin | 100000010111000010111001… |
… | …101101110001000010010111 |
3 | 200122220202202210102120010222 |
4 | 200113002321231301002113 |
5 | 122123242204414240201 |
6 | 1222405233520104555 |
7 | 41656235552442122 |
oct | 4027027155610227 |
9 | 618822683376128 |
10 | 142321152102551 |
11 | 4139107506a014 |
12 | 13b66961a6515b |
13 | 6154a9a072386 |
14 | 27205481c73b9 |
15 | 116c176b1c91b |
hex | 8170b9b71097 |
142321152102551 has 4 divisors (see below), whose sum is σ = 142324331016504. Its totient is φ = 142317973188600.
The previous prime is 142321152102517. The next prime is 142321152102553. The reversal of 142321152102551 is 155201251123241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 142321152102551 - 214 = 142321152086167 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142321152102553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1589389820 + ... + 1589479361.
It is an arithmetic number, because the mean of its divisors is an integer number (35581082754126).
Almost surely, 2142321152102551 is an apocalyptic number.
142321152102551 is a deficient number, since it is larger than the sum of its proper divisors (3178913953).
142321152102551 is an equidigital number, since it uses as much as digits as its factorization.
142321152102551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3178913952.
The product of its (nonzero) digits is 24000, while the sum is 35.
The spelling of 142321152102551 in words is "one hundred forty-two trillion, three hundred twenty-one billion, one hundred fifty-two million, one hundred two thousand, five hundred fifty-one".
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