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142321204143303 = 347440401381101
BaseRepresentation
bin100000010111000010111100…
…110100010010010011000111
3200122220202220102100111122020
4200113002330310102103013
5122123242311230041203
61222405243015334223
741656240053666333
oct4027027464222307
9618822812314566
10142321204143303
11413910a1483aa9
1213b66977381373
136154aa7a93613
1427205510927c3
15116c17b49c153
hex8170bcd124c7

142321204143303 has 4 divisors (see below), whose sum is σ = 189761605524408. Its totient is φ = 94880802762200.

The previous prime is 142321204143259. The next prime is 142321204143323. The reversal of 142321204143303 is 303341402123241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 142321204143303 - 28 = 142321204143047 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142321204143323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23720200690548 + ... + 23720200690553.

It is an arithmetic number, because the mean of its divisors is an integer number (47440401381102).

Almost surely, 2142321204143303 is an apocalyptic number.

142321204143303 is a deficient number, since it is larger than the sum of its proper divisors (47440401381105).

142321204143303 is an equidigital number, since it uses as much as digits as its factorization.

142321204143303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47440401381104.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 142321204143303 its reverse (303341402123241), we get a palindrome (445662606266544).

The spelling of 142321204143303 in words is "one hundred forty-two trillion, three hundred twenty-one billion, two hundred four million, one hundred forty-three thousand, three hundred three".

Divisors: 1 3 47440401381101 142321204143303