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142321231041397 is a prime number
BaseRepresentation
bin100000010111000010111110…
…011010111001001101110101
3200122220202222021222001212221
4200113002332122321031311
5122123242340121311042
61222405245420042341
741656240531425412
oct4027027632711565
9618822867861787
10142321231041397
1141391105685a31
1213b669843933b1
136154ab0520755
142720554895109
15116c17da11d67
hex8170be6b9375

142321231041397 has 2 divisors, whose sum is σ = 142321231041398. Its totient is φ = 142321231041396.

The previous prime is 142321231041389. The next prime is 142321231041413. The reversal of 142321231041397 is 793140132123241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 139910123946321 + 2411107095076 = 11828361^2 + 1552774^2 .

It is a cyclic number.

It is not a de Polignac number, because 142321231041397 - 23 = 142321231041389 is a prime.

It is a super-3 number, since 3×1423212310413973 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142321231041307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71160615520698 + 71160615520699.

It is an arithmetic number, because the mean of its divisors is an integer number (71160615520699).

Almost surely, 2142321231041397 is an apocalyptic number.

It is an amenable number.

142321231041397 is a deficient number, since it is larger than the sum of its proper divisors (1).

142321231041397 is an equidigital number, since it uses as much as digits as its factorization.

142321231041397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 217728, while the sum is 43.

The spelling of 142321231041397 in words is "one hundred forty-two trillion, three hundred twenty-one billion, two hundred thirty-one million, forty-one thousand, three hundred ninety-seven".