Base | Representation |
---|---|
bin | 11010100000100110… |
… | …10001001000111111 |
3 | 1100201212021010020001 |
4 | 31100103101020333 |
5 | 213121411130421 |
6 | 10312123535131 |
7 | 1012454052463 |
oct | 152023211077 |
9 | 40655233201 |
10 | 14232130111 |
11 | 6043737001 |
12 | 291238a4a7 |
13 | 145a735884 |
14 | 9902604a3 |
15 | 5846d7691 |
hex | 3504d123f |
14232130111 has 2 divisors, whose sum is σ = 14232130112. Its totient is φ = 14232130110.
The previous prime is 14232130007. The next prime is 14232130117. The reversal of 14232130111 is 11103123241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14232130111 - 211 = 14232128063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14232130117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7116065055 + 7116065056.
It is an arithmetic number, because the mean of its divisors is an integer number (7116065056).
Almost surely, 214232130111 is an apocalyptic number.
14232130111 is a deficient number, since it is larger than the sum of its proper divisors (1).
14232130111 is an equidigital number, since it uses as much as digits as its factorization.
14232130111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 14232130111 its reverse (11103123241), we get a palindrome (25335253352).
The spelling of 14232130111 in words is "fourteen billion, two hundred thirty-two million, one hundred thirty thousand, one hundred eleven".
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