Base | Representation |
---|---|
bin | 11010100000100110… |
… | …10001011011100100 |
3 | 1100201212021011212002 |
4 | 31100103101123210 |
5 | 213121411200200 |
6 | 10312123544432 |
7 | 1012454056112 |
oct | 152023213344 |
9 | 40655234762 |
10 | 14232131300 |
11 | 6043737992 |
12 | 291238b118 |
13 | 145a73628a |
14 | 990260ab2 |
15 | 5846d7bd5 |
hex | 3504d16e4 |
14232131300 has 18 divisors (see below), whose sum is σ = 30883725138. Its totient is φ = 5692852480.
The previous prime is 14232131299. The next prime is 14232131339. The reversal of 14232131300 is 313123241.
It can be written as a sum of positive squares in 3 ways, for example, as 66846976 + 14165284324 = 8176^2 + 119018^2 .
It is a super-2 number, since 2×142321313002 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 71160557 + ... + 71160756.
Almost surely, 214232131300 is an apocalyptic number.
14232131300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14232131300 is an abundant number, since it is smaller than the sum of its proper divisors (16651593838).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14232131300 is a wasteful number, since it uses less digits than its factorization.
14232131300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 142321327 (or 142321320 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 14232131300 its reverse (313123241), we get a palindrome (14545254541).
The spelling of 14232131300 in words is "fourteen billion, two hundred thirty-two million, one hundred thirty-one thousand, three hundred".
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