Base | Representation |
---|---|
bin | 100000010111000100111011… |
… | …110101101111111001100111 |
3 | 200122220222101221101002021222 |
4 | 200113010323311233321213 |
5 | 122123311142304430002 |
6 | 1222410234304130555 |
7 | 41656343631651236 |
oct | 4027047365577147 |
9 | 618828357332258 |
10 | 142323335233127 |
11 | 41391a95417364 |
12 | 13b67271006a5b |
13 | 6155057448509 |
14 | 27206b4112b1d |
15 | 116c2536061a2 |
hex | 81713bd6fe67 |
142323335233127 has 2 divisors, whose sum is σ = 142323335233128. Its totient is φ = 142323335233126.
The previous prime is 142323335233109. The next prime is 142323335233217. The reversal of 142323335233127 is 721332533323241.
Together with next prime (142323335233217) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 142323335233127 - 210 = 142323335232103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142323335235127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71161667616563 + 71161667616564.
It is an arithmetic number, because the mean of its divisors is an integer number (71161667616564).
Almost surely, 2142323335233127 is an apocalyptic number.
142323335233127 is a deficient number, since it is larger than the sum of its proper divisors (1).
142323335233127 is an equidigital number, since it uses as much as digits as its factorization.
142323335233127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1632960, while the sum is 44.
Adding to 142323335233127 its reverse (721332533323241), we get a palindrome (863655868556368).
The spelling of 142323335233127 in words is "one hundred forty-two trillion, three hundred twenty-three billion, three hundred thirty-five million, two hundred thirty-three thousand, one hundred twenty-seven".
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