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142323531101293 is a prime number
BaseRepresentation
bin100000010111000101000111…
…100000111011010001101101
3200122220222220120221012220111
4200113011013200323101231
5122123312042430220133
61222410305542220021
741656351530546403
oct4027050740732155
9618828816835814
10142323531101293
1141392085a37a83
1213b67306724611
136155088bb6c39
1427206d213b473
15116c2658e61cd
hex81714783b46d

142323531101293 has 2 divisors, whose sum is σ = 142323531101294. Its totient is φ = 142323531101292.

The previous prime is 142323531101263. The next prime is 142323531101321. The reversal of 142323531101293 is 392101135323241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134114859155209 + 8208671946084 = 11580797^2 + 2865078^2 .

It is a cyclic number.

It is not a de Polignac number, because 142323531101293 - 229 = 142322994230381 is a prime.

It is a super-2 number, since 2×1423235311012932 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142323531101263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71161765550646 + 71161765550647.

It is an arithmetic number, because the mean of its divisors is an integer number (71161765550647).

Almost surely, 2142323531101293 is an apocalyptic number.

It is an amenable number.

142323531101293 is a deficient number, since it is larger than the sum of its proper divisors (1).

142323531101293 is an equidigital number, since it uses as much as digits as its factorization.

142323531101293 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 116640, while the sum is 40.

The spelling of 142323531101293 in words is "one hundred forty-two trillion, three hundred twenty-three billion, five hundred thirty-one million, one hundred one thousand, two hundred ninety-three".