Base | Representation |
---|---|
bin | 100000010111000111011011… |
… | …100010011101011010000011 |
3 | 200122221020022122221112022001 |
4 | 200113013123202131122003 |
5 | 122123332134204444303 |
6 | 1222411400214524431 |
7 | 41656500214423006 |
oct | 4027073342353203 |
9 | 618836278845261 |
10 | 142326014531203 |
11 | 4139313a853698 |
12 | 13b6789a366717 |
13 | 61553935641a9 |
14 | 2720889cb753d |
15 | 116c35d94c31d |
hex | 8171db89d683 |
142326014531203 has 2 divisors, whose sum is σ = 142326014531204. Its totient is φ = 142326014531202.
The previous prime is 142326014531179. The next prime is 142326014531209. The reversal of 142326014531203 is 302135410623241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142326014531203 - 225 = 142325980976771 is a prime.
It is not a weakly prime, because it can be changed into another prime (142326014531209) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71163007265601 + 71163007265602.
It is an arithmetic number, because the mean of its divisors is an integer number (71163007265602).
Almost surely, 2142326014531203 is an apocalyptic number.
142326014531203 is a deficient number, since it is larger than the sum of its proper divisors (1).
142326014531203 is an equidigital number, since it uses as much as digits as its factorization.
142326014531203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 103680, while the sum is 37.
The spelling of 142326014531203 in words is "one hundred forty-two trillion, three hundred twenty-six billion, fourteen million, five hundred thirty-one thousand, two hundred three".
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