Base | Representation |
---|---|
bin | 11010100000110100… |
… | …11101000100110011 |
3 | 1100201222210211102211 |
4 | 31100122131010303 |
5 | 213122401422003 |
6 | 10312232152551 |
7 | 1012506060046 |
oct | 152032350463 |
9 | 40658724384 |
10 | 14234014003 |
11 | 6044803440 |
12 | 2912b38757 |
13 | 145ac451c1 |
14 | 9905d0c5d |
15 | 58495a96d |
hex | 35069d133 |
14234014003 has 4 divisors (see below), whose sum is σ = 15528015288. Its totient is φ = 12940012720.
The previous prime is 14234013961. The next prime is 14234014013. The reversal of 14234014003 is 30041043241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14234014003 - 29 = 14234013491 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14234014013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 647000626 + ... + 647000647.
It is an arithmetic number, because the mean of its divisors is an integer number (3882003822).
Almost surely, 214234014003 is an apocalyptic number.
14234014003 is a deficient number, since it is larger than the sum of its proper divisors (1294001285).
14234014003 is a wasteful number, since it uses less digits than its factorization.
14234014003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1294001284.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 14234014003 its reverse (30041043241), we get a palindrome (44275057244).
The spelling of 14234014003 in words is "fourteen billion, two hundred thirty-four million, fourteen thousand, three".
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