Base | Representation |
---|---|
bin | 1100111100100010000100… |
… | …0110100101101111110011 |
3 | 1212101202122022002022202002 |
4 | 3033020201012211233303 |
5 | 3331202342202311142 |
6 | 50135013353244215 |
7 | 2666243461104644 |
oct | 317104106455763 |
9 | 55352568068662 |
10 | 14234076994547 |
11 | 45987024221a3 |
12 | 171a7ab70366b |
13 | 7c33631a7007 |
14 | 372d0c2316cb |
15 | 19a3dad7ea32 |
hex | cf2211a5bf3 |
14234076994547 has 2 divisors, whose sum is σ = 14234076994548. Its totient is φ = 14234076994546.
The previous prime is 14234076994541. The next prime is 14234076994601. The reversal of 14234076994547 is 74549967043241.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14234076994547 is a prime.
It is not a weakly prime, because it can be changed into another prime (14234076994541) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7117038497273 + 7117038497274.
It is an arithmetic number, because the mean of its divisors is an integer number (7117038497274).
Almost surely, 214234076994547 is an apocalyptic number.
14234076994547 is a deficient number, since it is larger than the sum of its proper divisors (1).
14234076994547 is an equidigital number, since it uses as much as digits as its factorization.
14234076994547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 182891520, while the sum is 65.
The spelling of 14234076994547 in words is "fourteen trillion, two hundred thirty-four billion, seventy-six million, nine hundred ninety-four thousand, five hundred forty-seven".
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