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14234210051 = 472691125857
BaseRepresentation
bin11010100000110110…
…01100111100000011
31100202000011210100212
431100123030330003
5213122424210201
610312240304335
71012510534445
oct152033147403
940660153325
1014234210051
116044927766
1229130120ab
13145acb34c9
14990642495
15584998abb
hex3506ccf03

14234210051 has 8 divisors (see below), whose sum is σ = 14591119680. Its totient is φ = 13879552768.

The previous prime is 14234210027. The next prime is 14234210057. The reversal of 14234210051 is 15001243241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14234210051 - 214 = 14234193667 is a prime.

It is a super-2 number, since 2×142342100512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14234209999 and 14234210026.

It is not an unprimeable number, because it can be changed into a prime (14234210057) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 550286 + ... + 575571.

It is an arithmetic number, because the mean of its divisors is an integer number (1823889960).

Almost surely, 214234210051 is an apocalyptic number.

14234210051 is a deficient number, since it is larger than the sum of its proper divisors (356909629).

14234210051 is a wasteful number, since it uses less digits than its factorization.

14234210051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1126173.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 14234210051 its reverse (15001243241), we get a palindrome (29235453292).

The spelling of 14234210051 in words is "fourteen billion, two hundred thirty-four million, two hundred ten thousand, fifty-one".

Divisors: 1 47 269 12643 1125857 52915279 302855533 14234210051