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142342130131 is a prime number
BaseRepresentation
bin1000010010010001000…
…0001000100111010011
3111121102001211102021121
42010210100020213103
54313004041131011
6145220245503111
713166241100015
oct2044420104723
9447361742247
10142342130131
1155404470183
1223706111a97
1310565b98406
146c647061b5
153a81665e71
hex21244089d3

142342130131 has 2 divisors, whose sum is σ = 142342130132. Its totient is φ = 142342130130.

The previous prime is 142342130081. The next prime is 142342130179. The reversal of 142342130131 is 131031243241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 142342130131 - 211 = 142342128083 is a prime.

It is a super-2 number, since 2×1423421301312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 142342130096 and 142342130105.

It is not a weakly prime, because it can be changed into another prime (142342130431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71171065065 + 71171065066.

It is an arithmetic number, because the mean of its divisors is an integer number (71171065066).

Almost surely, 2142342130131 is an apocalyptic number.

142342130131 is a deficient number, since it is larger than the sum of its proper divisors (1).

142342130131 is an equidigital number, since it uses as much as digits as its factorization.

142342130131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 142342130131 its reverse (131031243241), we get a palindrome (273373373372).

The spelling of 142342130131 in words is "one hundred forty-two billion, three hundred forty-two million, one hundred thirty thousand, one hundred thirty-one".