Search a number
-
+
14234258657 is a prime number
BaseRepresentation
bin11010100000110110…
…11000110011100001
31100202000021021001002
431100123120303201
5213122432234112
610312241321345
71012511126243
oct152033306341
940660237032
1014234258657
116044960233
122913036255
13145accc678
14990656093
155849a81c2
hex3506d8ce1

14234258657 has 2 divisors, whose sum is σ = 14234258658. Its totient is φ = 14234258656.

The previous prime is 14234258651. The next prime is 14234258659. The reversal of 14234258657 is 75685243241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12071636641 + 2162622016 = 109871^2 + 46504^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14234258657 is a prime.

It is a super-2 number, since 2×142342586572 (a number of 21 digits) contains 22 as substring.

Together with 14234258659, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14234258651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7117129328 + 7117129329.

It is an arithmetic number, because the mean of its divisors is an integer number (7117129329).

Almost surely, 214234258657 is an apocalyptic number.

It is an amenable number.

14234258657 is a deficient number, since it is larger than the sum of its proper divisors (1).

14234258657 is an equidigital number, since it uses as much as digits as its factorization.

14234258657 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1612800, while the sum is 47.

The spelling of 14234258657 in words is "fourteen billion, two hundred thirty-four million, two hundred fifty-eight thousand, six hundred fifty-seven".