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14234331434 = 27117165717
BaseRepresentation
bin11010100000110111…
…01010100100101010
31100202000101221212112
431100123222210222
5213122442101214
610312243042322
71012511551361
oct152033524452
940660357775
1014234331434
1160449aa984
1229130703a2
13145b02682b
149906747d8
155849bea3e
hex3506ea92a

14234331434 has 4 divisors (see below), whose sum is σ = 21351497154. Its totient is φ = 7117165716.

The previous prime is 14234331401. The next prime is 14234331437. The reversal of 14234331434 is 43413343241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43413343241 = 172553726073.

It can be written as a sum of positive squares in only one way, i.e., 12917004409 + 1317327025 = 113653^2 + 36295^2 .

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 14234331434.

It is not an unprimeable number, because it can be changed into a prime (14234331437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3558582857 + ... + 3558582860.

Almost surely, 214234331434 is an apocalyptic number.

14234331434 is a deficient number, since it is larger than the sum of its proper divisors (7117165720).

14234331434 is an equidigital number, since it uses as much as digits as its factorization.

14234331434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7117165719.

The product of its digits is 41472, while the sum is 32.

Adding to 14234331434 its reverse (43413343241), we get a palindrome (57647674675).

The spelling of 14234331434 in words is "fourteen billion, two hundred thirty-four million, three hundred thirty-one thousand, four hundred thirty-four".

Divisors: 1 2 7117165717 14234331434