Base | Representation |
---|---|
bin | 1100111100100011000100… |
… | …0001100001001010010001 |
3 | 1212101210022220200201020001 |
4 | 3033020301001201022101 |
5 | 3331203414042203442 |
6 | 50135100054250001 |
7 | 2666253213343333 |
oct | 317106101411221 |
9 | 55353286621201 |
10 | 14234344100497 |
11 | 459882a179914 |
12 | 171a865056901 |
13 | 7c33a6628781 |
14 | 372d358c1453 |
15 | 19a4045422b7 |
hex | cf231061291 |
14234344100497 has 2 divisors, whose sum is σ = 14234344100498. Its totient is φ = 14234344100496.
The previous prime is 14234344100429. The next prime is 14234344100503. The reversal of 14234344100497 is 79400144343241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7156823450176 + 7077520650321 = 2675224^2 + 2660361^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14234344100497 is a prime.
It is not a weakly prime, because it can be changed into another prime (14234344100797) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7117172050248 + 7117172050249.
It is an arithmetic number, because the mean of its divisors is an integer number (7117172050249).
Almost surely, 214234344100497 is an apocalyptic number.
It is an amenable number.
14234344100497 is a deficient number, since it is larger than the sum of its proper divisors (1).
14234344100497 is an equidigital number, since it uses as much as digits as its factorization.
14234344100497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1161216, while the sum is 46.
The spelling of 14234344100497 in words is "fourteen trillion, two hundred thirty-four billion, three hundred forty-four million, one hundred thousand, four hundred ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •