Search a number
-
+
142359030257 is a prime number
BaseRepresentation
bin1000010010010101000…
…0100110100111110001
3111121110020122000220012
42010211100212213301
54313022402432012
6145222052024305
713166534535353
oct2044520464761
9447406560805
10142359030257
1155412a63524
122370b902095
13105695348a2
146c66a650d3
153a82da3622
hex21254269f1

142359030257 has 2 divisors, whose sum is σ = 142359030258. Its totient is φ = 142359030256.

The previous prime is 142359030227. The next prime is 142359030259. The reversal of 142359030257 is 752030953241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125956849216 + 16402181041 = 354904^2 + 128071^2 .

It is a cyclic number.

It is not a de Polignac number, because 142359030257 - 210 = 142359029233 is a prime.

Together with 142359030259, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (142359030259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71179515128 + 71179515129.

It is an arithmetic number, because the mean of its divisors is an integer number (71179515129).

Almost surely, 2142359030257 is an apocalyptic number.

It is an amenable number.

142359030257 is a deficient number, since it is larger than the sum of its proper divisors (1).

142359030257 is an equidigital number, since it uses as much as digits as its factorization.

142359030257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 226800, while the sum is 41.

Adding to 142359030257 its reverse (752030953241), we get a palindrome (894389983498).

The spelling of 142359030257 in words is "one hundred forty-two billion, three hundred fifty-nine million, thirty thousand, two hundred fifty-seven".