1423958403713 has 4 divisors (see below), whose sum is σ = 1437783242688. Its totient is φ = 1410133564740.

The previous prime is 1423958403683. The next prime is 1423958403733. The reversal of 1423958403713 is 3173048593241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1423958403713 - 2¹⁰ = 1423958402689 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1423958403733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6912419333 + ... + 6912419538.

It is an arithmetic number, because the mean of its divisors is an integer number (359445810672).

Almost surely, 2^{1423958403713} is an apocalyptic number.

It is an amenable number.

1423958403713 is a deficient number, since it is larger than the sum of its proper divisors (13824838975).

1423958403713 is a wasteful number, since it uses less digits than its factorization.

1423958403713 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13824838974.

The product of its (nonzero) digits is 2177280, while the sum is 50.

The spelling of 1423958403713 in words is "one trillion, four hundred twenty-three billion, nine hundred fifty-eight million, four hundred three thousand, seven hundred thirteen".