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14241024231403 is a prime number
BaseRepresentation
bin1100111100111011111100…
…1100001100011111101011
31212102102120110112112002211
43033032333030030133223
53331311104200401103
650142123004505551
72666610566460544
oct317167714143753
955372513475084
1014241024231403
1145a0647a09062
12172000a24b2b7
137c3bcc597c58
143733aab754cb
1519a695c2536d
hexcf3bf30c7eb

14241024231403 has 2 divisors, whose sum is σ = 14241024231404. Its totient is φ = 14241024231402.

The previous prime is 14241024231391. The next prime is 14241024231433. The reversal of 14241024231403 is 30413242014241.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (30413242014241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14241024231403 - 213 = 14241024223211 is a prime.

It is not a weakly prime, because it can be changed into another prime (14241024231433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7120512115701 + 7120512115702.

It is an arithmetic number, because the mean of its divisors is an integer number (7120512115702).

Almost surely, 214241024231403 is an apocalyptic number.

14241024231403 is a deficient number, since it is larger than the sum of its proper divisors (1).

14241024231403 is an equidigital number, since it uses as much as digits as its factorization.

14241024231403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 14241024231403 its reverse (30413242014241), we get a palindrome (44654266245644).

The spelling of 14241024231403 in words is "fourteen trillion, two hundred forty-one billion, twenty-four million, two hundred thirty-one thousand, four hundred three".