Base | Representation |
---|---|
bin | 100000011000010111100011… |
… | …001100110110101011100111 |
3 | 200200020110101002121122120201 |
4 | 200120113203030312223213 |
5 | 122131234330330244312 |
6 | 1222515104503211331 |
7 | 41665634112464053 |
oct | 4030274314665347 |
9 | 620213332548521 |
10 | 142412042431207 |
11 | 4141667630720a |
12 | 13b804a8a46b47 |
13 | 6160523482c33 |
14 | 2724acb444c63 |
15 | 116e6e6215557 |
hex | 8185e3336ae7 |
142412042431207 has 2 divisors, whose sum is σ = 142412042431208. Its totient is φ = 142412042431206.
The previous prime is 142412042431171. The next prime is 142412042431531. The reversal of 142412042431207 is 702134240214241.
142412042431207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142412042431207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142412042435207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71206021215603 + 71206021215604.
It is an arithmetic number, because the mean of its divisors is an integer number (71206021215604).
Almost surely, 2142412042431207 is an apocalyptic number.
142412042431207 is a deficient number, since it is larger than the sum of its proper divisors (1).
142412042431207 is an equidigital number, since it uses as much as digits as its factorization.
142412042431207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86016, while the sum is 37.
Adding to 142412042431207 its reverse (702134240214241), we get a palindrome (844546282645448).
The spelling of 142412042431207 in words is "one hundred forty-two trillion, four hundred twelve billion, forty-two million, four hundred thirty-one thousand, two hundred seven".
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